The trick in this puzzle is that you are allows to weigh just once and you have to figure out the jar which contains the defective marbles. The solution is simple.
Take 1 marble from jar 1,2 marbles from jar 2, 3 marbles from jar 3 ........ 10 marbles from jar 10. Now weigh these marbles on the weighing machine. Let's say the sum is
549 grams.
Now ideally the sum should be 550 grams(1*10 + 2*10 + 3*10 ................10*10) if all the marbles were of same weight. This means that one marble is defective.So this marble will be from jar 1 as we have taken just 1 marble from jar 1.So this means that jar 1 contains the marbles weighing 9 grams.
Similarly if the weight shown by the machine is 548 grams that means that the jar 2 contains the defective marbles and so on.
Take 1 marble from jar 1,2 marbles from jar 2, 3 marbles from jar 3 ........ 10 marbles from jar 10. Now weigh these marbles on the weighing machine. Let's say the sum is
549 grams.
Now ideally the sum should be 550 grams(1*10 + 2*10 + 3*10 ................10*10) if all the marbles were of same weight. This means that one marble is defective.So this marble will be from jar 1 as we have taken just 1 marble from jar 1.So this means that jar 1 contains the marbles weighing 9 grams.
Similarly if the weight shown by the machine is 548 grams that means that the jar 2 contains the defective marbles and so on.
2 comments:
supper...
Nice explanation.
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