The solution is easy. Mark the buckets from 1 to 10 and pick one ball from 1 bucket.
2 balls from 2nd bucket.
3 balls from 3rd bucket and so on.
till
10 balls from 10th bucket.
Now weigh them on the weighing machine and check your reading.
let's say it displays 54.9 grams.
Ideally it should have been 55 grams if all the balls were of 1 gram so since there is a difference of 0.1 gram in the solution therefore
bucket no 1 contains the balls weighing 0.9 gram.
Similarly it can be predicted depending upon the weight displayed by the weighing balance.
2 balls from 2nd bucket.
3 balls from 3rd bucket and so on.
till
10 balls from 10th bucket.
Now weigh them on the weighing machine and check your reading.
let's say it displays 54.9 grams.
Ideally it should have been 55 grams if all the balls were of 1 gram so since there is a difference of 0.1 gram in the solution therefore
bucket no 1 contains the balls weighing 0.9 gram.
Similarly it can be predicted depending upon the weight displayed by the weighing balance.
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